1296+729=c^2

Solution for 1296+729=c^2 equation:

1296+729=c^2

We move all terms to the left:

1296+729-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+2025=0

a = -1; b = 0; c = +2025;
Δ = b2-4ac
Δ = 02-4·(-1)·2025
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*-1}=\frac{-90}{-2}
=+45
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*-1}=\frac{90}{-2}
=-45
$